Base | Representation |
---|---|
bin | 10100110111010100… |
… | …00000001111111101 |
3 | 1001220122102210111102 |
4 | 22123222000033331 |
5 | 140420030223031 |
6 | 5051301102445 |
7 | 544403310041 |
oct | 123352001775 |
9 | 31818383442 |
10 | 11201414141 |
11 | 48289a7265 |
12 | 22073b7a25 |
13 | 1096888508 |
14 | 783940021 |
15 | 4585c77cb |
hex | 29ba803fd |
11201414141 has 2 divisors, whose sum is σ = 11201414142. Its totient is φ = 11201414140.
The previous prime is 11201414131. The next prime is 11201414183. The reversal of 11201414141 is 14141410211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9614586916 + 1586827225 = 98054^2 + 39835^2 .
It is an emirp because it is prime and its reverse (14141410211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11201414141 - 222 = 11197219837 is a prime.
It is a super-3 number, since 3×112014141413 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11201414131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600707070 + 5600707071.
It is an arithmetic number, because the mean of its divisors is an integer number (5600707071).
Almost surely, 211201414141 is an apocalyptic number.
It is an amenable number.
11201414141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201414141 is an equidigital number, since it uses as much as digits as its factorization.
11201414141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 11201414141 its reverse (14141410211), we get a palindrome (25342824352).
The spelling of 11201414141 in words is "eleven billion, two hundred one million, four hundred fourteen thousand, one hundred forty-one".
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