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112014243413 is a prime number
BaseRepresentation
bin110100001010010010…
…0011011011001010101
3101201010110120010212222
41220110210123121111
53313401121242123
6123243021552125
711043550234142
oct1502444333125
9351113503788
10112014243413
1143561135a96
1219861415645
13a7418c0407
1455c89093c9
152da8d706c8
hex1a1491b655

112014243413 has 2 divisors, whose sum is σ = 112014243414. Its totient is φ = 112014243412.

The previous prime is 112014243379. The next prime is 112014243427. The reversal of 112014243413 is 314342410211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59508187249 + 52506056164 = 243943^2 + 229142^2 .

It is an emirp because it is prime and its reverse (314342410211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112014243413 - 214 = 112014227029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112014243493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56007121706 + 56007121707.

It is an arithmetic number, because the mean of its divisors is an integer number (56007121707).

Almost surely, 2112014243413 is an apocalyptic number.

It is an amenable number.

112014243413 is a deficient number, since it is larger than the sum of its proper divisors (1).

112014243413 is an equidigital number, since it uses as much as digits as its factorization.

112014243413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 112014243413 its reverse (314342410211), we get a palindrome (426356653624).

The spelling of 112014243413 in words is "one hundred twelve billion, fourteen million, two hundred forty-three thousand, four hundred thirteen".