Base | Representation |
---|---|
bin | 110100001010011001… |
… | …0110100100111000011 |
3 | 101201010201122211212121 |
4 | 1220110302310213003 |
5 | 3313403103013312 |
6 | 123243234505111 |
7 | 11043624301042 |
oct | 1502462644703 |
9 | 351121584777 |
10 | 112018016707 |
11 | 43563282a13 |
12 | 19862735197 |
13 | a742611a2c |
14 | 55c920c559 |
15 | 2da9368707 |
hex | 1a14cb49c3 |
112018016707 has 2 divisors, whose sum is σ = 112018016708. Its totient is φ = 112018016706.
The previous prime is 112018016687. The next prime is 112018016711. The reversal of 112018016707 is 707610810211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112018016707 is a prime.
It is a super-2 number, since 2×1120180167072 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112018013707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56009008353 + 56009008354.
It is an arithmetic number, because the mean of its divisors is an integer number (56009008354).
Almost surely, 2112018016707 is an apocalyptic number.
112018016707 is a deficient number, since it is larger than the sum of its proper divisors (1).
112018016707 is an equidigital number, since it uses as much as digits as its factorization.
112018016707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4704, while the sum is 34.
Adding to 112018016707 its reverse (707610810211), we get a palindrome (819628826918).
The spelling of 112018016707 in words is "one hundred twelve billion, eighteen million, sixteen thousand, seven hundred seven".
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