Base | Representation |
---|---|
bin | 10000010011010000111… |
… | …111011101111011110011 |
3 | 10222002102111210002111101 |
4 | 100103100333131323303 |
5 | 121323131113424241 |
6 | 2214340050225231 |
7 | 143634355104631 |
oct | 20232077357363 |
9 | 3862374702441 |
10 | 1120197795571 |
11 | 3a20894a7828 |
12 | 161127b85217 |
13 | 818324479ba |
14 | 3c309b5a351 |
15 | 1e213c8ce31 |
hex | 104d0fddef3 |
1120197795571 has 2 divisors, whose sum is σ = 1120197795572. Its totient is φ = 1120197795570.
The previous prime is 1120197795533. The next prime is 1120197795581. The reversal of 1120197795571 is 1755977910211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120197795571 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120197795581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560098897785 + 560098897786.
It is an arithmetic number, because the mean of its divisors is an integer number (560098897786).
Almost surely, 21120197795571 is an apocalyptic number.
1120197795571 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120197795571 is an equidigital number, since it uses as much as digits as its factorization.
1120197795571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1389150, while the sum is 55.
The spelling of 1120197795571 in words is "one trillion, one hundred twenty billion, one hundred ninety-seven million, seven hundred ninety-five thousand, five hundred seventy-one".
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