Base | Representation |
---|---|
bin | 10000010011010001010… |
… | …000010110001001101111 |
3 | 10222002102211002212212102 |
4 | 100103101100112021233 |
5 | 121323133232021033 |
6 | 2214340325125315 |
7 | 143634440523356 |
oct | 20232120261157 |
9 | 3862384085772 |
10 | 1120202220143 |
11 | 3a2090a49aa6 |
12 | 16112955983b |
13 | 818333368a6 |
14 | 3c30a58c99d |
15 | 1e214363de8 |
hex | 104d141626f |
1120202220143 has 2 divisors, whose sum is σ = 1120202220144. Its totient is φ = 1120202220142.
The previous prime is 1120202220101. The next prime is 1120202220157. The reversal of 1120202220143 is 3410222020211.
It is a strong prime.
It is an emirp because it is prime and its reverse (3410222020211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1120202220143 - 218 = 1120201957999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120202225143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560101110071 + 560101110072.
It is an arithmetic number, because the mean of its divisors is an integer number (560101110072).
Almost surely, 21120202220143 is an apocalyptic number.
1120202220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120202220143 is an equidigital number, since it uses as much as digits as its factorization.
1120202220143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1120202220143 its reverse (3410222020211), we get a palindrome (4530424240354).
The spelling of 1120202220143 in words is "one trillion, one hundred twenty billion, two hundred two million, two hundred twenty thousand, one hundred forty-three".
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