Base | Representation |
---|---|
bin | 10000010011010001010… |
… | …011101101100000101011 |
3 | 10222002102212202200220002 |
4 | 100103101103231200223 |
5 | 121323133443233001 |
6 | 2214340400053215 |
7 | 143634451156202 |
oct | 20232123554053 |
9 | 3862385680802 |
10 | 1120203102251 |
11 | 3a20914a1812 |
12 | 16112990420b |
13 | 8183358524c |
14 | 3c30a73c239 |
15 | 1e21448a46b |
hex | 104d14ed82b |
1120203102251 has 2 divisors, whose sum is σ = 1120203102252. Its totient is φ = 1120203102250.
The previous prime is 1120203102181. The next prime is 1120203102253. The reversal of 1120203102251 is 1522013020211.
It is a strong prime.
It is an emirp because it is prime and its reverse (1522013020211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120203102251 is a prime.
It is a super-2 number, since 2×11202031022512 (a number of 25 digits) contains 22 as substring.
Together with 1120203102253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1120203102253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560101551125 + 560101551126.
It is an arithmetic number, because the mean of its divisors is an integer number (560101551126).
Almost surely, 21120203102251 is an apocalyptic number.
1120203102251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120203102251 is an equidigital number, since it uses as much as digits as its factorization.
1120203102251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 1120203102251 its reverse (1522013020211), we get a palindrome (2642216122462).
The spelling of 1120203102251 in words is "one trillion, one hundred twenty billion, two hundred three million, one hundred two thousand, two hundred fifty-one".
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