Base | Representation |
---|---|
bin | 1010001100000011000101… |
… | …0000100011100010001000 |
3 | 1110122220120200120220020022 |
4 | 2203000301100203202020 |
5 | 2432013400342201100 |
6 | 35454101344120012 |
7 | 2234216336356004 |
oct | 243006120434210 |
9 | 43586520526208 |
10 | 11202101131400 |
11 | 362986a061243 |
12 | 130b061006008 |
13 | 633479b3903a |
14 | 2aa282719704 |
15 | 1465d431ae85 |
hex | a3031423888 |
11202101131400 has 48 divisors (see below), whose sum is σ = 26650580154000. Its totient is φ = 4376634857280.
The previous prime is 11202101131381. The next prime is 11202101131423. The reversal of 11202101131400 is 413110120211.
It is a super-2 number, since 2×112021011314002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 651276350 + ... + 651293549.
It is an arithmetic number, because the mean of its divisors is an integer number (555220419875).
Almost surely, 211202101131400 is an apocalyptic number.
11202101131400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11202101131400 is an abundant number, since it is smaller than the sum of its proper divisors (15448479022600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11202101131400 is a wasteful number, since it uses less digits than its factorization.
11202101131400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1302569958 (or 1302569949 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11202101131400 its reverse (413110120211), we get a palindrome (11615211251611).
The spelling of 11202101131400 in words is "eleven trillion, two hundred two billion, one hundred one million, one hundred thirty-one thousand, four hundred".
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