Base | Representation |
---|---|
bin | 10000010011010001101… |
… | …111010010100101110011 |
3 | 10222002110101101000021021 |
4 | 100103101233102211303 |
5 | 121323142321111034 |
6 | 2214341215040311 |
7 | 143634566500222 |
oct | 20232157224563 |
9 | 3862411330237 |
10 | 1120210332019 |
11 | 3a209558a629 |
12 | 161130210097 |
13 | 81834c16c0c |
14 | 3c30b6a0cb9 |
15 | 1e214e176b4 |
hex | 104d1bd2973 |
1120210332019 has 2 divisors, whose sum is σ = 1120210332020. Its totient is φ = 1120210332018.
The previous prime is 1120210331993. The next prime is 1120210332029. The reversal of 1120210332019 is 9102330120211.
It is a strong prime.
It is an emirp because it is prime and its reverse (9102330120211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1120210332019 - 217 = 1120210200947 is a prime.
It is a super-2 number, since 2×11202103320192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1120210331984 and 1120210332002.
It is not a weakly prime, because it can be changed into another prime (1120210332029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560105166009 + 560105166010.
It is an arithmetic number, because the mean of its divisors is an integer number (560105166010).
Almost surely, 21120210332019 is an apocalyptic number.
1120210332019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120210332019 is an equidigital number, since it uses as much as digits as its factorization.
1120210332019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 1120210332019 in words is "one trillion, one hundred twenty billion, two hundred ten million, three hundred thirty-two thousand, nineteen".
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