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112022110101133 is a prime number
BaseRepresentation
bin11001011110001000101110…
…000101000101111010001101
3112200122012122110110010220201
4121132020232011011322031
5104140332240141214013
61034130125201013501
732411221214006101
oct3136105605057215
9480565573403821
10112022110101133
113276a345818231
1210692776024291
134a67841426bbb
141d93c83031901
15ce3e4381b3dd
hex65e22e145e8d

112022110101133 has 2 divisors, whose sum is σ = 112022110101134. Its totient is φ = 112022110101132.

The previous prime is 112022110101073. The next prime is 112022110101169. The reversal of 112022110101133 is 331101011220211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68405107064644 + 43617003036489 = 8270738^2 + 6604317^2 .

It is an emirp because it is prime and its reverse (331101011220211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112022110101133 - 217 = 112022109970061 is a prime.

It is a super-2 number, since 2×1120221101011332 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 112022110101133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112022510101133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56011055050566 + 56011055050567.

It is an arithmetic number, because the mean of its divisors is an integer number (56011055050567).

Almost surely, 2112022110101133 is an apocalyptic number.

It is an amenable number.

112022110101133 is a deficient number, since it is larger than the sum of its proper divisors (1).

112022110101133 is an equidigital number, since it uses as much as digits as its factorization.

112022110101133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 112022110101133 its reverse (331101011220211), we get a palindrome (443123121321344).

The spelling of 112022110101133 in words is "one hundred twelve trillion, twenty-two billion, one hundred ten million, one hundred one thousand, one hundred thirty-three".