Base | Representation |
---|---|
bin | 1101010110101… |
… | …10111011111001 |
3 | 21210210200111021 |
4 | 12223112323321 |
5 | 212134420213 |
6 | 15041102441 |
7 | 2530143265 |
oct | 653267371 |
9 | 253720437 |
10 | 112029433 |
11 | 5826840a |
12 | 31627a21 |
13 | 1a296009 |
14 | 10c430a5 |
15 | 9c7dd8d |
hex | 6ad6ef9 |
112029433 has 2 divisors, whose sum is σ = 112029434. Its totient is φ = 112029432.
The previous prime is 112029419. The next prime is 112029457. The reversal of 112029433 is 334920211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111260304 + 769129 = 10548^2 + 877^2 .
It is a cyclic number.
It is not a de Polignac number, because 112029433 - 213 = 112021241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112029398 and 112029407.
It is not a weakly prime, because it can be changed into another prime (112024433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56014716 + 56014717.
It is an arithmetic number, because the mean of its divisors is an integer number (56014717).
Almost surely, 2112029433 is an apocalyptic number.
It is an amenable number.
112029433 is a deficient number, since it is larger than the sum of its proper divisors (1).
112029433 is an equidigital number, since it uses as much as digits as its factorization.
112029433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
The square root of 112029433 is about 10584.3957314530. The cubic root of 112029433 is about 482.0706739685.
Adding to 112029433 its reverse (334920211), we get a palindrome (446949644).
The spelling of 112029433 in words is "one hundred twelve million, twenty-nine thousand, four hundred thirty-three".
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