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11203011311214 = 231867168551869
BaseRepresentation
bin1010001100000110011110…
…0000100111011001101110
31110122222221010020211012210
42203001213200213121232
52432022231343424324
635454331540311250
72234251030643322
oct243014740473156
943588833224183
1011203011311214
11362a196906868
12130b2759a2526
13633593588088
142aa32b565982
151466391a8d29
hexa306782766e

11203011311214 has 8 divisors (see below), whose sum is σ = 22406022622440. Its totient is φ = 3734337103736.

The previous prime is 11203011311209. The next prime is 11203011311237. The reversal of 11203011311214 is 41211311030211.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

11203011311214 is an admirable number.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 933584275929 + ... + 933584275940.

It is an arithmetic number, because the mean of its divisors is an integer number (2800752827805).

Almost surely, 211203011311214 is an apocalyptic number.

11203011311214 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11203011311214 is a wasteful number, since it uses less digits than its factorization.

11203011311214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1867168551874.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 11203011311214 its reverse (41211311030211), we get a palindrome (52414322341425).

The spelling of 11203011311214 in words is "eleven trillion, two hundred three billion, eleven million, three hundred eleven thousand, two hundred fourteen".

Divisors: 1 2 3 6 1867168551869 3734337103738 5601505655607 11203011311214