Base | Representation |
---|---|
bin | 11001011110010000001011… |
… | …000110111000001001101111 |
3 | 112200122222022012212211100102 |
4 | 121132100023012320021233 |
5 | 104141000133001113403 |
6 | 1034133531253221315 |
7 | 32411623434044444 |
oct | 3136201306701157 |
9 | 480588265784312 |
10 | 112030113301103 |
11 | 32772782380888 |
12 | 1069422a33183b |
13 | 4a6851851a69a |
14 | 1d94401ccd9cb |
15 | ce4261249b88 |
hex | 65e40b1b826f |
112030113301103 has 2 divisors, whose sum is σ = 112030113301104. Its totient is φ = 112030113301102.
The previous prime is 112030113301087. The next prime is 112030113301157. The reversal of 112030113301103 is 301103311030211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112030113301103 - 24 = 112030113301087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112030113306103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56015056650551 + 56015056650552.
It is an arithmetic number, because the mean of its divisors is an integer number (56015056650552).
Almost surely, 2112030113301103 is an apocalyptic number.
112030113301103 is a deficient number, since it is larger than the sum of its proper divisors (1).
112030113301103 is an equidigital number, since it uses as much as digits as its factorization.
112030113301103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 112030113301103 its reverse (301103311030211), we get a palindrome (413133424331314).
The spelling of 112030113301103 in words is "one hundred twelve trillion, thirty billion, one hundred thirteen million, three hundred one thousand, one hundred three".
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