Base | Representation |
---|---|
bin | 10000010011010111001… |
… | …101000011101001001001 |
3 | 10222002200202220022011121 |
4 | 100103113031003221021 |
5 | 121323334304134233 |
6 | 2214354252155241 |
7 | 143640062026465 |
oct | 20232715035111 |
9 | 3862622808147 |
10 | 1120302021193 |
11 | 3a2132315003 |
12 | 161156a68b21 |
13 | 8184ac0a974 |
14 | 3c31992b4a5 |
15 | 1e21cec992d |
hex | 104d7343a49 |
1120302021193 has 2 divisors, whose sum is σ = 1120302021194. Its totient is φ = 1120302021192.
The previous prime is 1120302021107. The next prime is 1120302021203. The reversal of 1120302021193 is 3911202030211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 768827341584 + 351474679609 = 876828^2 + 592853^2 .
It is a cyclic number.
It is not a de Polignac number, because 1120302021193 - 237 = 982863067721 is a prime.
It is a super-2 number, since 2×11203020211932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1120302021103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560151010596 + 560151010597.
It is an arithmetic number, because the mean of its divisors is an integer number (560151010597).
Almost surely, 21120302021193 is an apocalyptic number.
It is an amenable number.
1120302021193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120302021193 is an equidigital number, since it uses as much as digits as its factorization.
1120302021193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 1120302021193 in words is "one trillion, one hundred twenty billion, three hundred two million, twenty-one thousand, one hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •