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11203022143 = 13185519253
BaseRepresentation
bin10100110111100000…
…01000110100111111
31001220202110111021001
422123300020310333
5140420433202033
65051355351131
7544423055065
oct123360106477
931822414231
1011203022143
1148298a5395
122207a524a7
131096ccc3b1
14783c3c035
154587e3e7d
hex29bc08d3f

11203022143 has 4 divisors (see below), whose sum is σ = 11288541528. Its totient is φ = 11117502760.

The previous prime is 11203022119. The next prime is 11203022147. The reversal of 11203022143 is 34122030211.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11203022143 - 217 = 11202891071 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11203022143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11203022147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42759496 + ... + 42759757.

It is an arithmetic number, because the mean of its divisors is an integer number (2822135382).

Almost surely, 211203022143 is an apocalyptic number.

11203022143 is a deficient number, since it is larger than the sum of its proper divisors (85519385).

11203022143 is an equidigital number, since it uses as much as digits as its factorization.

11203022143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85519384.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 11203022143 its reverse (34122030211), we get a palindrome (45325052354).

The spelling of 11203022143 in words is "eleven billion, two hundred three million, twenty-two thousand, one hundred forty-three".

Divisors: 1 131 85519253 11203022143