Base | Representation |
---|---|
bin | 110100001010110110… |
… | …0101111110000111011 |
3 | 101201011210020022002122 |
4 | 1220111230233300323 |
5 | 3313420444414321 |
6 | 123244540151455 |
7 | 11044200332531 |
oct | 1502554576073 |
9 | 351153208078 |
10 | 112033201211 |
11 | 43570904298 |
12 | 1986783858b |
13 | a7457ca349 |
14 | 55cb242151 |
15 | 2daa8678ab |
hex | 1a15b2fc3b |
112033201211 has 2 divisors, whose sum is σ = 112033201212. Its totient is φ = 112033201210.
The previous prime is 112033201199. The next prime is 112033201213. The reversal of 112033201211 is 112102330211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112033201211 - 214 = 112033184827 is a prime.
It is a super-3 number, since 3×1120332012113 (a number of 34 digits) contains 333 as substring.
Together with 112033201213, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112033201211.
It is not a weakly prime, because it can be changed into another prime (112033201213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56016600605 + 56016600606.
It is an arithmetic number, because the mean of its divisors is an integer number (56016600606).
Almost surely, 2112033201211 is an apocalyptic number.
112033201211 is a deficient number, since it is larger than the sum of its proper divisors (1).
112033201211 is an equidigital number, since it uses as much as digits as its factorization.
112033201211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 112033201211 its reverse (112102330211), we get a palindrome (224135531422).
The spelling of 112033201211 in words is "one hundred twelve billion, thirty-three million, two hundred one thousand, two hundred eleven".
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