Base | Representation |
---|---|
bin | 10000010011011001000… |
… | …011101110110011100101 |
3 | 10222002202221102211202222 |
4 | 100103121003232303211 |
5 | 121323420240142411 |
6 | 2214401323042125 |
7 | 143640620326541 |
oct | 20233103566345 |
9 | 3862687384688 |
10 | 1120333130981 |
11 | 3a2148933279 |
12 | 161165370345 |
13 | 818544b0b1c |
14 | 3c31db08a21 |
15 | 1e220ac24db |
hex | 104d90eece5 |
1120333130981 has 2 divisors, whose sum is σ = 1120333130982. Its totient is φ = 1120333130980.
The previous prime is 1120333130963. The next prime is 1120333131097. The reversal of 1120333130981 is 1890313330211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 707674642756 + 412658488225 = 841234^2 + 642385^2 .
It is an emirp because it is prime and its reverse (1890313330211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120333130981 is a prime.
It is a super-2 number, since 2×11203331309812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120333130281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560166565490 + 560166565491.
It is an arithmetic number, because the mean of its divisors is an integer number (560166565491).
Almost surely, 21120333130981 is an apocalyptic number.
It is an amenable number.
1120333130981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120333130981 is an equidigital number, since it uses as much as digits as its factorization.
1120333130981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 1120333130981 in words is "one trillion, one hundred twenty billion, three hundred thirty-three million, one hundred thirty thousand, nine hundred eighty-one".
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