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1120344028253 is a prime number
BaseRepresentation
bin10000010011011001101…
…101010011010001011101
310222002210200221111000122
4100103121231103101131
5121323431032401003
62214402352404325
7143641112054162
oct20233155232135
93862720844018
101120344028253
113a2153aa658a
12161168b466a5
1381856827c08
143c321344069
151e221a26238
hex104d9b5345d

1120344028253 has 2 divisors, whose sum is σ = 1120344028254. Its totient is φ = 1120344028252.

The previous prime is 1120344028241. The next prime is 1120344028303. The reversal of 1120344028253 is 3528204430211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 981284397604 + 139059630649 = 990598^2 + 372907^2 .

It is an emirp because it is prime and its reverse (3528204430211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1120344028253 - 212 = 1120344024157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1120344028753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560172014126 + 560172014127.

It is an arithmetic number, because the mean of its divisors is an integer number (560172014127).

Almost surely, 21120344028253 is an apocalyptic number.

It is an amenable number.

1120344028253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120344028253 is an equidigital number, since it uses as much as digits as its factorization.

1120344028253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 1120344028253 its reverse (3528204430211), we get a palindrome (4648548458464).

The spelling of 1120344028253 in words is "one trillion, one hundred twenty billion, three hundred forty-four million, twenty-eight thousand, two hundred fifty-three".