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112040113 is a prime number
BaseRepresentation
bin1101010110110…
…01100010110001
321210211020010211
412223121202301
5212140240423
615041224121
72530216363
oct653314261
9253736124
10112040113
1158275439
1231632041
131a29ab33
1410c46d33
159c8210d
hex6ad98b1

112040113 has 2 divisors, whose sum is σ = 112040114. Its totient is φ = 112040112.

The previous prime is 112040087. The next prime is 112040143. The reversal of 112040113 is 311040211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82955664 + 29084449 = 9108^2 + 5393^2 .

It is a cyclic number.

It is not a de Polignac number, because 112040113 - 225 = 78485681 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112040093 and 112040102.

It is not a weakly prime, because it can be changed into another prime (112040143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56020056 + 56020057.

It is an arithmetic number, because the mean of its divisors is an integer number (56020057).

Almost surely, 2112040113 is an apocalyptic number.

It is an amenable number.

112040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112040113 is an equidigital number, since it uses as much as digits as its factorization.

112040113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 112040113 is about 10584.9002357131. The cubic root of 112040113 is about 482.0859924167.

Adding to 112040113 its reverse (311040211), we get a palindrome (423080324).

The spelling of 112040113 in words is "one hundred twelve million, forty thousand, one hundred thirteen".