Base | Representation |
---|---|
bin | 10000010011011110111… |
… | …001111010010100001111 |
3 | 10222010000210000021120222 |
4 | 100103132321322110033 |
5 | 121324120343014413 |
6 | 2214415145301555 |
7 | 143643221142365 |
oct | 20233671722417 |
9 | 3863023007528 |
10 | 1120431219983 |
11 | 3a2199239a69 |
12 | 1611921948bb |
13 | 8186b90585a |
14 | 3c32cb5d635 |
15 | 1e2294eab08 |
hex | 104dee7a50f |
1120431219983 has 2 divisors, whose sum is σ = 1120431219984. Its totient is φ = 1120431219982.
The previous prime is 1120431219967. The next prime is 1120431220031. The reversal of 1120431219983 is 3899121340211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1120431219983 - 24 = 1120431219967 is a prime.
It is a super-2 number, since 2×11204312199832 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120431219913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560215609991 + 560215609992.
It is an arithmetic number, because the mean of its divisors is an integer number (560215609992).
Almost surely, 21120431219983 is an apocalyptic number.
1120431219983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120431219983 is an equidigital number, since it uses as much as digits as its factorization.
1120431219983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 44.
The spelling of 1120431219983 in words is "one trillion, one hundred twenty billion, four hundred thirty-one million, two hundred nineteen thousand, nine hundred eighty-three".
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