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11204432533100 = 2252112044325331
BaseRepresentation
bin1010001100001011110000…
…1110001001011001101100
31110200010121011112101010102
42203002330032021121230
52432033134212024400
635455124550130232
72234331166064342
oct243027416113154
943603534471112
1011204432533100
11362a85607a904
12130b5b1950978
1363375bb57181
142aa4241dd992
151466bdd419d5
hexa30bc38966c

11204432533100 has 18 divisors (see below), whose sum is σ = 24313618597044. Its totient is φ = 4481773013200.

The previous prime is 11204432533093. The next prime is 11204432533121. The reversal of 11204432533100 is 133523440211.

It is a super-2 number, since 2×112044325331002 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56022162566 + ... + 56022162765.

Almost surely, 211204432533100 is an apocalyptic number.

11204432533100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11204432533100 is an abundant number, since it is smaller than the sum of its proper divisors (13109186063944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11204432533100 is a wasteful number, since it uses less digits than its factorization.

11204432533100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112044325345 (or 112044325338 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 11204432533100 its reverse (133523440211), we get a palindrome (11337955973311).

The spelling of 11204432533100 in words is "eleven trillion, two hundred four billion, four hundred thirty-two million, five hundred thirty-three thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 112044325331 224088650662 448177301324 560221626655 1120443253310 2240886506620 2801108133275 5602216266550 11204432533100