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112054143332 = 22172396894791
BaseRepresentation
bin110100001011011110…
…0101000100101100100
3101201020020122021021202
41220112330220211210
53313441330041312
6123251005102032
711044543334345
oct1502674504544
9351206567252
10112054143332
114358170842a
1219872857918
13a749c50531
1455cdd340cc
152dac6029c2
hex1a16f28964

112054143332 has 24 divisors (see below), whose sum is σ = 208498510080. Its totient is φ = 52510720640.

The previous prime is 112054143319. The next prime is 112054143343. The reversal of 112054143332 is 233341450211.

It is a super-2 number, since 2×1120541433322 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112054143295 and 112054143304.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3431144 + ... + 3463647.

It is an arithmetic number, because the mean of its divisors is an integer number (8687437920).

Almost surely, 2112054143332 is an apocalyptic number.

It is an amenable number.

112054143332 is a deficient number, since it is larger than the sum of its proper divisors (96444366748).

112054143332 is a wasteful number, since it uses less digits than its factorization.

112054143332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6895051 (or 6895049 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 112054143332 its reverse (233341450211), we get a palindrome (345395593543).

The spelling of 112054143332 in words is "one hundred twelve billion, fifty-four million, one hundred forty-three thousand, three hundred thirty-two".

Divisors: 1 2 4 17 34 68 239 478 956 4063 8126 16252 6894791 13789582 27579164 117211447 234422894 468845788 1647855049 3295710098 6591420196 28013535833 56027071666 112054143332