Base | Representation |
---|---|
bin | 1010001100010011100010… |
… | …1010000011101110111111 |
3 | 1110200022222122220002121122 |
4 | 2203010320222003232333 |
5 | 2432101423134142303 |
6 | 35500112044421155 |
7 | 2234434006135646 |
oct | 243047052035677 |
9 | 43608878802548 |
10 | 11206520224703 |
11 | 3630727571471 |
12 | 130ba94b477bb |
13 | 633a0252584b |
14 | 2aa5815a435d |
15 | 146792276e38 |
hex | a3138a83bbf |
11206520224703 has 2 divisors, whose sum is σ = 11206520224704. Its totient is φ = 11206520224702.
The previous prime is 11206520224699. The next prime is 11206520224811. The reversal of 11206520224703 is 30742202560211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11206520224703 - 22 = 11206520224699 is a prime.
It is a super-2 number, since 2×112065202247032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11206520824703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5603260112351 + 5603260112352.
It is an arithmetic number, because the mean of its divisors is an integer number (5603260112352).
Almost surely, 211206520224703 is an apocalyptic number.
11206520224703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11206520224703 is an equidigital number, since it uses as much as digits as its factorization.
11206520224703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 11206520224703 its reverse (30742202560211), we get a palindrome (41948722784914).
The spelling of 11206520224703 in words is "eleven trillion, two hundred six billion, five hundred twenty million, two hundred twenty-four thousand, seven hundred three".
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