Base | Representation |
---|---|
bin | 1010001100100000100000… |
… | …1000111011010000000011 |
3 | 1110200122222020221222012111 |
4 | 2203020020020323100003 |
5 | 2432131040301401011 |
6 | 35501445314040151 |
7 | 2234616165011236 |
oct | 243101010732003 |
9 | 43618866858174 |
10 | 11210001200131 |
11 | 3632153484868 |
12 | 13106a6879057 |
13 | 634138760a16 |
14 | 2aa7d1a0d41d |
15 | 1468e7b77121 |
hex | a320823b403 |
11210001200131 has 2 divisors, whose sum is σ = 11210001200132. Its totient is φ = 11210001200130.
The previous prime is 11210001200093. The next prime is 11210001200143. The reversal of 11210001200131 is 13100210001211.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (13100210001211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11210001200131 - 29 = 11210001199619 is a prime.
It is a super-2 number, since 2×112100012001312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11210001200231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605000600065 + 5605000600066.
It is an arithmetic number, because the mean of its divisors is an integer number (5605000600066).
Almost surely, 211210001200131 is an apocalyptic number.
11210001200131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210001200131 is an equidigital number, since it uses as much as digits as its factorization.
11210001200131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11210001200131 its reverse (13100210001211), we get a palindrome (24310211201342).
The spelling of 11210001200131 in words is "eleven trillion, two hundred ten billion, one million, two hundred thousand, one hundred thirty-one".
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