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1121001010183 is a prime number
BaseRepresentation
bin10000010100000000110…
…111011111010000000111
310222011111111011121210201
4100110000313133100013
5121331302224311213
62214551502031331
7143663310240325
oct20240067372007
93864444147721
101121001010183
113a246093385a
12161310b78547
138192c984b12
143c3846c0d15
151e25e54c6dd
hex10500ddf407

1121001010183 has 2 divisors, whose sum is σ = 1121001010184. Its totient is φ = 1121001010182.

The previous prime is 1121001010153. The next prime is 1121001010219. The reversal of 1121001010183 is 3810101001211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1121001010183 - 221 = 1120998913031 is a prime.

It is a super-3 number, since 3×11210010101833 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1121001010183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121001010123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560500505091 + 560500505092.

It is an arithmetic number, because the mean of its divisors is an integer number (560500505092).

Almost surely, 21121001010183 is an apocalyptic number.

1121001010183 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121001010183 is an equidigital number, since it uses as much as digits as its factorization.

1121001010183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1121001010183 its reverse (3810101001211), we get a palindrome (4931102011394).

The spelling of 1121001010183 in words is "one trillion, one hundred twenty-one billion, one million, ten thousand, one hundred eighty-three".