11210010131 has 2 divisors, whose sum is σ = 11210010132. Its totient is φ = 11210010130.

The previous prime is 11210010113. The next prime is 11210010143. The reversal of 11210010131 is 13101001211.

It is a happy number.

Together with previous prime (11210010113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13101001211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11210010131 is a prime.

It is a super-2 number, since 2×11210010131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11210019131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605005065 + 5605005066.

It is an arithmetic number, because the mean of its divisors is an integer number (5605005066).

Almost surely, 2^11210010131 is an apocalyptic number.

11210010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11210010131 is an equidigital number, since it uses as much as digits as its factorization.

11210010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11210010131 its reverse (13101001211), we get a palindrome (24311011342).

The spelling of 11210010131 in words is "eleven billion, two hundred ten million, ten thousand, one hundred thirty-one".