Base | Representation |
---|---|
bin | 10000010100000000111… |
… | …000010000000010011011 |
3 | 10222011111111112202220202 |
4 | 100110000320100002123 |
5 | 121331302302210021 |
6 | 2214551510212415 |
7 | 143663312032034 |
oct | 20240070200233 |
9 | 3864444482822 |
10 | 1121001210011 |
11 | 3a2460a5aa01 |
12 | 16131105410b |
13 | 8192ca24a67 |
14 | 3c384733a8b |
15 | 1e25e58ba0b |
hex | 10500e1009b |
1121001210011 has 2 divisors, whose sum is σ = 1121001210012. Its totient is φ = 1121001210010.
The previous prime is 1121001209971. The next prime is 1121001210013. The reversal of 1121001210011 is 1100121001211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121001210011 - 26 = 1121001209947 is a prime.
It is a super-2 number, since 2×11210012100112 (a number of 25 digits) contains 22 as substring.
Together with 1121001210013, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1121001209974 and 1121001210001.
It is not a weakly prime, because it can be changed into another prime (1121001210013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560500605005 + 560500605006.
It is an arithmetic number, because the mean of its divisors is an integer number (560500605006).
Almost surely, 21121001210011 is an apocalyptic number.
1121001210011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121001210011 is an equidigital number, since it uses as much as digits as its factorization.
1121001210011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1121001210011 its reverse (1100121001211), we get a palindrome (2221122211222).
The spelling of 1121001210011 in words is "one trillion, one hundred twenty-one billion, one million, two hundred ten thousand, eleven".
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