Base | Representation |
---|---|
bin | 11001011111010001011101… |
… | …010001001011111110101011 |
3 | 112200220200020110110200000001 |
4 | 121133101131101023332223 |
5 | 104143122213032242303 |
6 | 1034230043122523431 |
7 | 32416654510336264 |
oct | 3137213521137653 |
9 | 480820213420001 |
10 | 112100211212203 |
11 | 3279a483867a15 |
12 | 106a5931b06577 |
13 | 4a7200a026aa6 |
14 | 1d9797191196b |
15 | ce5eb524b31d |
hex | 65f45d44bfab |
112100211212203 has 2 divisors, whose sum is σ = 112100211212204. Its totient is φ = 112100211212202.
The previous prime is 112100211212177. The next prime is 112100211212239. The reversal of 112100211212203 is 302212112001211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112100211212203 is a prime.
It is a super-2 number, since 2×1121002112122032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112100211212273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050105606101 + 56050105606102.
It is an arithmetic number, because the mean of its divisors is an integer number (56050105606102).
Almost surely, 2112100211212203 is an apocalyptic number.
112100211212203 is a deficient number, since it is larger than the sum of its proper divisors (1).
112100211212203 is an equidigital number, since it uses as much as digits as its factorization.
112100211212203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 112100211212203 its reverse (302212112001211), we get a palindrome (414312323213414).
The spelling of 112100211212203 in words is "one hundred twelve trillion, one hundred billion, two hundred eleven million, two hundred twelve thousand, two hundred three".
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