Base | Representation |
---|---|
bin | 1010001100100000101000… |
… | …0010101010010001000101 |
3 | 1110200200001111000021020111 |
4 | 2203020022002222101011 |
5 | 2432131121434042013 |
6 | 35501452414033021 |
7 | 2234620033162162 |
oct | 243101202522105 |
9 | 43620044007214 |
10 | 11210033112133 |
11 | 363216a4a0819 |
12 | 13106b54a8771 |
13 | 63414225506b |
14 | 2aa7d5d59069 |
15 | 1468ea87c73d |
hex | a320a0aa445 |
11210033112133 has 2 divisors, whose sum is σ = 11210033112134. Its totient is φ = 11210033112132.
The previous prime is 11210033112127. The next prime is 11210033112169. The reversal of 11210033112133 is 33121133001211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8473466890084 + 2736566222049 = 2910922^2 + 1654257^2 .
It is a cyclic number.
It is not a de Polignac number, because 11210033112133 - 25 = 11210033112101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210033122133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605016556066 + 5605016556067.
It is an arithmetic number, because the mean of its divisors is an integer number (5605016556067).
Almost surely, 211210033112133 is an apocalyptic number.
It is an amenable number.
11210033112133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210033112133 is an equidigital number, since it uses as much as digits as its factorization.
11210033112133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11210033112133 its reverse (33121133001211), we get a palindrome (44331166113344).
The spelling of 11210033112133 in words is "eleven trillion, two hundred ten billion, thirty-three million, one hundred twelve thousand, one hundred thirty-three".
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