Base | Representation |
---|---|
bin | 11001011111010010001100… |
… | …010010100110100000010011 |
3 | 112200220202021102220221021111 |
4 | 121133102030102212200103 |
5 | 104143130322012042042 |
6 | 1034230253303434151 |
7 | 32420013200022154 |
oct | 3137221422464023 |
9 | 480822242827244 |
10 | 112101000112147 |
11 | 3279a849107142 |
12 | 106a5b12155957 |
13 | 4a721045c14a7 |
14 | 1d97a085cb92b |
15 | ce600e62e517 |
hex | 65f48c4a6813 |
112101000112147 has 2 divisors, whose sum is σ = 112101000112148. Its totient is φ = 112101000112146.
The previous prime is 112101000111937. The next prime is 112101000112201. The reversal of 112101000112147 is 741211000101211.
It is a strong prime.
It is an emirp because it is prime and its reverse (741211000101211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112101000112147 is a prime.
It is a super-2 number, since 2×1121010001121472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112101000112547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050500056073 + 56050500056074.
It is an arithmetic number, because the mean of its divisors is an integer number (56050500056074).
Almost surely, 2112101000112147 is an apocalyptic number.
112101000112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
112101000112147 is an equidigital number, since it uses as much as digits as its factorization.
112101000112147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 112101000112147 its reverse (741211000101211), we get a palindrome (853312000213358).
The spelling of 112101000112147 in words is "one hundred twelve trillion, one hundred one billion, one hundred twelve thousand, one hundred forty-seven".
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