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11210101101131 is a prime number
BaseRepresentation
bin1010001100100000111000…
…0110000001001001001011
31110200200020012221110121112
42203020032012001021023
52432131241340214011
635501503243200535
72234621520111632
oct243101606011113
943620205843545
1011210101101131
1136321a4908979
12131071421614b
1363415336b43a
142aa800db6519
1514690180c58b
hexa320e18124b

11210101101131 has 2 divisors, whose sum is σ = 11210101101132. Its totient is φ = 11210101101130.

The previous prime is 11210101101103. The next prime is 11210101101247. The reversal of 11210101101131 is 13110110101211.

It is a weak prime.

It is an emirp because it is prime and its reverse (13110110101211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11210101101131 - 214 = 11210101084747 is a prime.

It is a super-2 number, since 2×112101011011312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11210101101431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605050550565 + 5605050550566.

It is an arithmetic number, because the mean of its divisors is an integer number (5605050550566).

Almost surely, 211210101101131 is an apocalyptic number.

11210101101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11210101101131 is an equidigital number, since it uses as much as digits as its factorization.

11210101101131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 14.

Adding to 11210101101131 its reverse (13110110101211), we get a palindrome (24320211202342).

The spelling of 11210101101131 in words is "eleven trillion, two hundred ten billion, one hundred one million, one hundred one thousand, one hundred thirty-one".