Base | Representation |
---|---|
bin | 1010001100100000111000… |
… | …0110000001001000101111 |
3 | 1110200200020012221110120111 |
4 | 2203020032012001020233 |
5 | 2432131241340213403 |
6 | 35501503243200451 |
7 | 2234621520111562 |
oct | 243101606011057 |
9 | 43620205843514 |
10 | 11210101101103 |
11 | 36321a4908953 |
12 | 1310714216127 |
13 | 63415336b418 |
14 | 2aa800db64d9 |
15 | 14690180c56d |
hex | a320e18122f |
11210101101103 has 2 divisors, whose sum is σ = 11210101101104. Its totient is φ = 11210101101102.
The previous prime is 11210101101097. The next prime is 11210101101131. The reversal of 11210101101103 is 30110110101211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11210101101103 - 217 = 11210100970031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210191101103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605050550551 + 5605050550552.
It is an arithmetic number, because the mean of its divisors is an integer number (5605050550552).
Almost surely, 211210101101103 is an apocalyptic number.
11210101101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210101101103 is an equidigital number, since it uses as much as digits as its factorization.
11210101101103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 11210101101103 its reverse (30110110101211), we get a palindrome (41320211202314).
The spelling of 11210101101103 in words is "eleven trillion, two hundred ten billion, one hundred one million, one hundred one thousand, one hundred three".
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