Base | Representation |
---|---|
bin | 10000010100000001011… |
… | …010001101001001111111 |
3 | 10222011112010021222220211 |
4 | 100110001122031021333 |
5 | 121331312042023403 |
6 | 2214552425053251 |
7 | 143663450503531 |
oct | 20240132151177 |
9 | 3864463258824 |
10 | 1121010111103 |
11 | 3a2465a8a483 |
12 | 161314027227 |
13 | 8193182038c |
14 | 3c3859ad851 |
15 | 1e26024906d |
hex | 1050168d27f |
1121010111103 has 2 divisors, whose sum is σ = 1121010111104. Its totient is φ = 1121010111102.
The previous prime is 1121010111049. The next prime is 1121010111139. The reversal of 1121010111103 is 3011110101211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121010111103 - 213 = 1121010102911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121010111503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560505055551 + 560505055552.
It is an arithmetic number, because the mean of its divisors is an integer number (560505055552).
Almost surely, 21121010111103 is an apocalyptic number.
1121010111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121010111103 is an equidigital number, since it uses as much as digits as its factorization.
1121010111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 1121010111103 its reverse (3011110101211), we get a palindrome (4132120212314).
The spelling of 1121010111103 in words is "one trillion, one hundred twenty-one billion, ten million, one hundred eleven thousand, one hundred three".
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