112101110101117 has 2 divisors, whose sum is σ = 112101110101118. Its totient is φ = 112101110101116.

The previous prime is 112101110101093. The next prime is 112101110101171. The reversal of 112101110101117 is 711101011101211.

Together with next prime (112101110101171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63255394462276 + 48845715638841 = 7953326^2 + 6988971^2 .

It is an emirp because it is prime and its reverse (711101011101211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112101110101117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112101110101094 and 112101110101103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112101110101187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050555050558 + 56050555050559.

It is an arithmetic number, because the mean of its divisors is an integer number (56050555050559).

Almost surely, 2^{112101110101117} is an apocalyptic number.

It is an amenable number.

112101110101117 is a deficient number, since it is larger than the sum of its proper divisors (1).

112101110101117 is an equidigital number, since it uses as much as digits as its factorization.

112101110101117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14, while the sum is 19.

Adding to 112101110101117 its reverse (711101011101211), we get a palindrome (823202121202328).

The spelling of 112101110101117 in words is "one hundred twelve trillion, one hundred one billion, one hundred ten million, one hundred one thousand, one hundred seventeen".