11210131412099 has 2 divisors, whose sum is σ = 11210131412100. Its totient is φ = 11210131412098.

The previous prime is 11210131412089. The next prime is 11210131412101. The reversal of 11210131412099 is 99021413101211.

It is a strong prime.

It is an emirp because it is prime and its reverse (99021413101211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11210131412099 - 2⁴⁰ = 10110619784323 is a prime.

Together with 11210131412101, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11210131412089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605065706049 + 5605065706050.

It is an arithmetic number, because the mean of its divisors is an integer number (5605065706050).

Almost surely, 2^{11210131412099} is an apocalyptic number.

11210131412099 is a deficient number, since it is larger than the sum of its proper divisors (1).

11210131412099 is an equidigital number, since it uses as much as digits as its factorization.

11210131412099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 35.

The spelling of 11210131412099 in words is "eleven trillion, two hundred ten billion, one hundred thirty-one million, four hundred twelve thousand, ninety-nine".