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112103003112173 is a prime number
BaseRepresentation
bin11001011111010100000011…
…101011011100001011101101
3112200220221110000220212202122
4121133110003223130023231
5104143143422244042143
61034231224135002325
732420113631160323
oct3137240353341355
9480827400825678
10112103003112173
11327a0686812767
12106a6390b093a5
134a723635791c8
141d97b58627d13
15ce60ca3d5c68
hex65f503adc2ed

112103003112173 has 2 divisors, whose sum is σ = 112103003112174. Its totient is φ = 112103003112172.

The previous prime is 112103003112103. The next prime is 112103003112227. The reversal of 112103003112173 is 371211300301211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101988548727844 + 10114454384329 = 10098938^2 + 3180323^2 .

It is a cyclic number.

It is not a de Polignac number, because 112103003112173 - 222 = 112102998917869 is a prime.

It is a super-3 number, since 3×1121030031121733 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112103003112103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051501556086 + 56051501556087.

It is an arithmetic number, because the mean of its divisors is an integer number (56051501556087).

Almost surely, 2112103003112173 is an apocalyptic number.

It is an amenable number.

112103003112173 is a deficient number, since it is larger than the sum of its proper divisors (1).

112103003112173 is an equidigital number, since it uses as much as digits as its factorization.

112103003112173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 26.

Adding to 112103003112173 its reverse (371211300301211), we get a palindrome (483314303413384).

The spelling of 112103003112173 in words is "one hundred twelve trillion, one hundred three billion, three million, one hundred twelve thousand, one hundred seventy-three".