Base | Representation |
---|---|
bin | 11001011111010100001010… |
… | …101001011010001100011101 |
3 | 112200220221202011220102111112 |
4 | 121133110022221122030131 |
5 | 104143144142211122003 |
6 | 1034231243512431405 |
7 | 32420116550653235 |
oct | 3137241251321435 |
9 | 480827664812445 |
10 | 112103120020253 |
11 | 327a073680250a |
12 | 106a64040a8565 |
13 | 4a7238185c99b |
14 | 1d97b69d7acc5 |
15 | ce60d57ca3d8 |
hex | 65f50aa5a31d |
112103120020253 has 2 divisors, whose sum is σ = 112103120020254. Its totient is φ = 112103120020252.
The previous prime is 112103120020223. The next prime is 112103120020273. The reversal of 112103120020253 is 352020021301211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98087096555449 + 14016023464804 = 9903893^2 + 3743798^2 .
It is a cyclic number.
It is not a de Polignac number, because 112103120020253 - 28 = 112103120019997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112103120020223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051560010126 + 56051560010127.
It is an arithmetic number, because the mean of its divisors is an integer number (56051560010127).
Almost surely, 2112103120020253 is an apocalyptic number.
It is an amenable number.
112103120020253 is a deficient number, since it is larger than the sum of its proper divisors (1).
112103120020253 is an equidigital number, since it uses as much as digits as its factorization.
112103120020253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 112103120020253 its reverse (352020021301211), we get a palindrome (464123141321464).
The spelling of 112103120020253 in words is "one hundred twelve trillion, one hundred three billion, one hundred twenty million, twenty thousand, two hundred fifty-three".
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