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1121031310303 is a prime number
BaseRepresentation
bin10000010100000010101…
…011000100101111011111
310222011120121012000202101
4100110002223010233133
5121331333003412203
62214554503305531
7143664125626012
oct20240253045737
93864517160671
101121031310303
113a2476a49783
1216131b14b2a7
1381936033598
143c38872b379
151e26203541d
hex10502ac4bdf

1121031310303 has 2 divisors, whose sum is σ = 1121031310304. Its totient is φ = 1121031310302.

The previous prime is 1121031310213. The next prime is 1121031310313. The reversal of 1121031310303 is 3030131301211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1121031310303 is a prime.

It is a super-2 number, since 2×11210313103032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121031310313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560515655151 + 560515655152.

It is an arithmetic number, because the mean of its divisors is an integer number (560515655152).

Almost surely, 21121031310303 is an apocalyptic number.

1121031310303 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121031310303 is an equidigital number, since it uses as much as digits as its factorization.

1121031310303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1121031310303 its reverse (3030131301211), we get a palindrome (4151162611514).

The spelling of 1121031310303 in words is "one trillion, one hundred twenty-one billion, thirty-one million, three hundred ten thousand, three hundred three".