Base | Representation |
---|---|
bin | 11001011111011010101010… |
… | …110000100000010010000101 |
3 | 112200221121202201020012120102 |
4 | 121133122222300200102011 |
5 | 104143302441401431203 |
6 | 1034234400335413445 |
7 | 32420454551015033 |
oct | 3137325260402205 |
9 | 480847681205512 |
10 | 112110101202053 |
11 | 327a3699473749 |
12 | 106a7832084285 |
13 | 4a72c24ca73a6 |
14 | 1d9822d1d9553 |
15 | ce6393628888 |
hex | 65f6aac20485 |
112110101202053 has 2 divisors, whose sum is σ = 112110101202054. Its totient is φ = 112110101202052.
The previous prime is 112110101201947. The next prime is 112110101202083. The reversal of 112110101202053 is 350202101011211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108035589396289 + 4074511805764 = 10394017^2 + 2018542^2 .
It is a cyclic number.
It is not a de Polignac number, because 112110101202053 - 28 = 112110101201797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112110101202083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055050601026 + 56055050601027.
It is an arithmetic number, because the mean of its divisors is an integer number (56055050601027).
Almost surely, 2112110101202053 is an apocalyptic number.
It is an amenable number.
112110101202053 is a deficient number, since it is larger than the sum of its proper divisors (1).
112110101202053 is an equidigital number, since it uses as much as digits as its factorization.
112110101202053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 112110101202053 its reverse (350202101011211), we get a palindrome (462312202213264).
The spelling of 112110101202053 in words is "one hundred twelve trillion, one hundred ten billion, one hundred one million, two hundred two thousand, fifty-three".
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