Search a number
-
+
1121102220113 is a prime number
BaseRepresentation
bin10000010100000110111…
…001100100101101010001
310222011202112121121201122
4100110012321210231101
5121332004132020423
62215005515212025
7143665646432111
oct20240671445521
93864675547648
101121102220113
113a2502a81327
1216133aa47015
1381947930255
143c393d09041
151e2683908c8
hex10506e64b51

1121102220113 has 2 divisors, whose sum is σ = 1121102220114. Its totient is φ = 1121102220112.

The previous prime is 1121102220083. The next prime is 1121102220197. The reversal of 1121102220113 is 3110222011211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 875856400384 + 245245819729 = 935872^2 + 495223^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121102220113 - 28 = 1121102219857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121102220091 and 1121102220100.

It is not a weakly prime, because it can be changed into another prime (1121102220613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560551110056 + 560551110057.

It is an arithmetic number, because the mean of its divisors is an integer number (560551110057).

Almost surely, 21121102220113 is an apocalyptic number.

It is an amenable number.

1121102220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121102220113 is an equidigital number, since it uses as much as digits as its factorization.

1121102220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1121102220113 its reverse (3110222011211), we get a palindrome (4231324231324).

The spelling of 1121102220113 in words is "one trillion, one hundred twenty-one billion, one hundred two million, two hundred twenty thousand, one hundred thirteen".