Base | Representation |
---|---|
bin | 10000010100000111010… |
… | …111010011010011010111 |
3 | 10222011210002021112202101 |
4 | 100110013113103103113 |
5 | 121332013130410033 |
6 | 2215010354222531 |
7 | 143666102610241 |
oct | 20240727232327 |
9 | 3864702245671 |
10 | 1121110013143 |
11 | 3a250741434a |
12 | 161341584a47 |
13 | 8194942b403 |
14 | 3c394d77091 |
15 | 1e268dce97d |
hex | 105075d34d7 |
1121110013143 has 2 divisors, whose sum is σ = 1121110013144. Its totient is φ = 1121110013142.
The previous prime is 1121110013081. The next prime is 1121110013197. The reversal of 1121110013143 is 3413100111211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121110013143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1121110013143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121110017143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560555006571 + 560555006572.
It is an arithmetic number, because the mean of its divisors is an integer number (560555006572).
Almost surely, 21121110013143 is an apocalyptic number.
1121110013143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121110013143 is an equidigital number, since it uses as much as digits as its factorization.
1121110013143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1121110013143 its reverse (3413100111211), we get a palindrome (4534210124354).
The spelling of 1121110013143 in words is "one trillion, one hundred twenty-one billion, one hundred ten million, thirteen thousand, one hundred forty-three".
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