Base | Representation |
---|---|
bin | 110100001101001010… |
… | …1100100000101100011 |
3 | 101201101012122101220002 |
4 | 1220122111210011203 |
5 | 3314100404311042 |
6 | 123300400010215 |
7 | 11046133601663 |
oct | 1503225440543 |
9 | 351335571802 |
10 | 112111010147 |
11 | 436008192a4 |
12 | 1988990096b |
13 | a758971336 |
14 | 55d76d81a3 |
15 | 2db25d7132 |
hex | 1a1a564163 |
112111010147 has 2 divisors, whose sum is σ = 112111010148. Its totient is φ = 112111010146.
The previous prime is 112111010087. The next prime is 112111010149. The reversal of 112111010147 is 741010111211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112111010147 - 216 = 112110944611 is a prime.
Together with 112111010149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (112111010149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055505073 + 56055505074.
It is an arithmetic number, because the mean of its divisors is an integer number (56055505074).
Almost surely, 2112111010147 is an apocalyptic number.
112111010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111010147 is an equidigital number, since it uses as much as digits as its factorization.
112111010147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 112111010147 its reverse (741010111211), we get a palindrome (853121121358).
The spelling of 112111010147 in words is "one hundred twelve billion, one hundred eleven million, ten thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •