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1121110212113 is a prime number
BaseRepresentation
bin10000010100000111011…
…000000011111000010001
310222011210002122122200122
4100110013120003320101
5121332013203241423
62215010402400025
7143666104366313
oct20240730037021
93864702578618
101121110212113
113a250753a891
12161341660015
138194949ab48
143c394dc97b3
151e268e1d8c8
hex10507603e11

1121110212113 has 2 divisors, whose sum is σ = 1121110212114. Its totient is φ = 1121110212112.

The previous prime is 1121110212109. The next prime is 1121110212119. The reversal of 1121110212113 is 3112120111211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1052323085584 + 68787126529 = 1025828^2 + 262273^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121110212113 - 22 = 1121110212109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121110212091 and 1121110212100.

It is not a weakly prime, because it can be changed into another prime (1121110212119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560555106056 + 560555106057.

It is an arithmetic number, because the mean of its divisors is an integer number (560555106057).

Almost surely, 21121110212113 is an apocalyptic number.

It is an amenable number.

1121110212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121110212113 is an equidigital number, since it uses as much as digits as its factorization.

1121110212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 1121110212113 its reverse (3112120111211), we get a palindrome (4233230323324).

The spelling of 1121110212113 in words is "one trillion, one hundred twenty-one billion, one hundred ten million, two hundred twelve thousand, one hundred thirteen".