Base | Representation |
---|---|
bin | 11001011111011011100001… |
… | …101110000100101000101111 |
3 | 112200221201010222100012210201 |
4 | 121133123201232010220233 |
5 | 104143311333431431112 |
6 | 1034235032035414331 |
7 | 32420516445556351 |
oct | 3137334156045057 |
9 | 480851128305721 |
10 | 112111023311407 |
11 | 327a4021a2709a |
12 | 106a7a4aa543a7 |
13 | 4a73041042323 |
14 | 1d982b986d0d1 |
15 | ce63e9571257 |
hex | 65f6e1b84a2f |
112111023311407 has 2 divisors, whose sum is σ = 112111023311408. Its totient is φ = 112111023311406.
The previous prime is 112111023311293. The next prime is 112111023311411. The reversal of 112111023311407 is 704113320111211.
It is a strong prime.
It is an emirp because it is prime and its reverse (704113320111211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112111023311407 - 27 = 112111023311279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112111023611407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055511655703 + 56055511655704.
It is an arithmetic number, because the mean of its divisors is an integer number (56055511655704).
Almost surely, 2112111023311407 is an apocalyptic number.
112111023311407 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111023311407 is an equidigital number, since it uses as much as digits as its factorization.
112111023311407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 28.
Adding to 112111023311407 its reverse (704113320111211), we get a palindrome (816224343422618).
The spelling of 112111023311407 in words is "one hundred twelve trillion, one hundred eleven billion, twenty-three million, three hundred eleven thousand, four hundred seven".
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