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1121111020153 is a prime number
BaseRepresentation
bin10000010100000111011…
…011001001001001111001
310222011210011011201010001
4100110013123021021321
5121332013410121103
62215010431553001
7143666114303155
oct20240733111171
93864704151101
101121111020153
113a2507a41993
1216134198b761
13819496c1887
143c39515a065
151e26902d01d
hex105076c9279

1121111020153 has 2 divisors, whose sum is σ = 1121111020154. Its totient is φ = 1121111020152.

The previous prime is 1121111020121. The next prime is 1121111020247. The reversal of 1121111020153 is 3510201111211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 566364615184 + 554746404969 = 752572^2 + 744813^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121111020153 - 25 = 1121111020121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1121111020153.

It is not a weakly prime, because it can be changed into another prime (1121111720153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560555510076 + 560555510077.

It is an arithmetic number, because the mean of its divisors is an integer number (560555510077).

Almost surely, 21121111020153 is an apocalyptic number.

It is an amenable number.

1121111020153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121111020153 is an equidigital number, since it uses as much as digits as its factorization.

1121111020153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 1121111020153 its reverse (3510201111211), we get a palindrome (4631312131364).

The spelling of 1121111020153 in words is "one trillion, one hundred twenty-one billion, one hundred eleven million, twenty thousand, one hundred fifty-three".