Base | Representation |
---|---|
bin | 110100001101001011… |
… | …0010101011001110111 |
3 | 101201101020000122222201 |
4 | 1220122112111121313 |
5 | 3314100432242101 |
6 | 123300404205331 |
7 | 11046135402631 |
oct | 1503226253167 |
9 | 351336018881 |
10 | 112111212151 |
11 | 43600947044 |
12 | 19889999847 |
13 | a758a12273 |
14 | 55d774ba51 |
15 | 2db2626e01 |
hex | 1a1a595677 |
112111212151 has 2 divisors, whose sum is σ = 112111212152. Its totient is φ = 112111212150.
The previous prime is 112111212107. The next prime is 112111212163. The reversal of 112111212151 is 151212111211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112111212151 - 213 = 112111203959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112111242151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055606075 + 56055606076.
It is an arithmetic number, because the mean of its divisors is an integer number (56055606076).
Almost surely, 2112111212151 is an apocalyptic number.
112111212151 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111212151 is an equidigital number, since it uses as much as digits as its factorization.
112111212151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40, while the sum is 19.
Adding to 112111212151 its reverse (151212111211), we get a palindrome (263323323362).
The spelling of 112111212151 in words is "one hundred twelve billion, one hundred eleven million, two hundred twelve thousand, one hundred fifty-one".
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