Base | Representation |
---|---|
bin | 10000010100000111011… |
… | …111101001001101010111 |
3 | 10222011210020101122120221 |
4 | 100110013133221031113 |
5 | 121332014210400043 |
6 | 2215010513135211 |
7 | 143666130316054 |
oct | 20240737511527 |
9 | 3864706348527 |
10 | 1121112200023 |
11 | 3a2508678392 |
12 | 16134225a507 |
13 | 81949a1591a |
14 | 3c39538602b |
15 | 1e2691b28ed |
hex | 105077e9357 |
1121112200023 has 2 divisors, whose sum is σ = 1121112200024. Its totient is φ = 1121112200022.
The previous prime is 1121112200017. The next prime is 1121112200051. The reversal of 1121112200023 is 3200022111211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121112200023 - 225 = 1121078645591 is a prime.
It is a super-2 number, since 2×11211122000232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121112200053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560556100011 + 560556100012.
It is an arithmetic number, because the mean of its divisors is an integer number (560556100012).
Almost surely, 21121112200023 is an apocalyptic number.
1121112200023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121112200023 is an equidigital number, since it uses as much as digits as its factorization.
1121112200023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1121112200023 its reverse (3200022111211), we get a palindrome (4321134311234).
The spelling of 1121112200023 in words is "one trillion, one hundred twenty-one billion, one hundred twelve million, two hundred thousand, twenty-three".
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