Base | Representation |
---|---|
bin | 10000010100000111100… |
… | …010101101010001011110 |
3 | 10222011210021220110012121 |
4 | 100110013202231101132 |
5 | 121332014412044402 |
6 | 2215010542253154 |
7 | 143666140202311 |
oct | 20240742552136 |
9 | 3864707813177 |
10 | 1121113003102 |
11 | 3a2509076794 |
12 | 1613425871ba |
13 | 81949c37311 |
14 | 3c395514978 |
15 | 1e2692c0837 |
hex | 105078ad45e |
1121113003102 has 4 divisors (see below), whose sum is σ = 1681669504656. Its totient is φ = 560556501550.
The previous prime is 1121113003093. The next prime is 1121113003139. The reversal of 1121113003102 is 2013003111211.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280278250774 + ... + 280278250777.
It is an arithmetic number, because the mean of its divisors is an integer number (420417376164).
Almost surely, 21121113003102 is an apocalyptic number.
1121113003102 is a deficient number, since it is larger than the sum of its proper divisors (560556501554).
1121113003102 is an equidigital number, since it uses as much as digits as its factorization.
1121113003102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 560556501553.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 1121113003102 its reverse (2013003111211), we get a palindrome (3134116114313).
The spelling of 1121113003102 in words is "one trillion, one hundred twenty-one billion, one hundred thirteen million, three thousand, one hundred two".
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