Base | Representation |
---|---|
bin | 10000010100000111101… |
… | …000100101000000110101 |
3 | 10222011210101210122100202 |
4 | 100110013220211000311 |
5 | 121332020310322013 |
6 | 2215011035250245 |
7 | 143666156242265 |
oct | 20240750450065 |
9 | 3864711718322 |
10 | 1121114542133 |
11 | 3a2509a28013 |
12 | 161342ba9985 |
13 | 8194a3559a1 |
14 | 3c3957d57a5 |
15 | 1e2694c6858 |
hex | 10507a25035 |
1121114542133 has 2 divisors, whose sum is σ = 1121114542134. Its totient is φ = 1121114542132.
The previous prime is 1121114542123. The next prime is 1121114542139. The reversal of 1121114542133 is 3312454111211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1087853172004 + 33261370129 = 1043002^2 + 182377^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121114542133 - 220 = 1121113493557 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1121114542096 and 1121114542105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121114542139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560557271066 + 560557271067.
It is an arithmetic number, because the mean of its divisors is an integer number (560557271067).
Almost surely, 21121114542133 is an apocalyptic number.
It is an amenable number.
1121114542133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121114542133 is an equidigital number, since it uses as much as digits as its factorization.
1121114542133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2880, while the sum is 29.
Adding to 1121114542133 its reverse (3312454111211), we get a palindrome (4433568653344).
The spelling of 1121114542133 in words is "one trillion, one hundred twenty-one billion, one hundred fourteen million, five hundred forty-two thousand, one hundred thirty-three".
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