Base | Representation |
---|---|
bin | 1010001100100100111110… |
… | …1001111000000011001111 |
3 | 1110200210001212122010210112 |
4 | 2203021033221320003033 |
5 | 2432141014430120421 |
6 | 35502204334230235 |
7 | 2234661004216541 |
oct | 243111751700317 |
9 | 43623055563715 |
10 | 11211201020111 |
11 | 3632709778324 |
12 | 131098065537b |
13 | 63429a1c1281 |
14 | 2aa8a70d3691 |
15 | 14696817945b |
hex | a324fa780cf |
11211201020111 has 2 divisors, whose sum is σ = 11211201020112. Its totient is φ = 11211201020110.
The previous prime is 11211201020069. The next prime is 11211201020171. The reversal of 11211201020111 is 11102010211211.
11211201020111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11211201020111 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11211201020171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605600510055 + 5605600510056.
It is an arithmetic number, because the mean of its divisors is an integer number (5605600510056).
Almost surely, 211211201020111 is an apocalyptic number.
11211201020111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211201020111 is an equidigital number, since it uses as much as digits as its factorization.
11211201020111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 11211201020111 its reverse (11102010211211), we get a palindrome (22313211231322).
The spelling of 11211201020111 in words is "eleven trillion, two hundred eleven billion, two hundred one million, twenty thousand, one hundred eleven".
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