112112013401 has 2 divisors, whose sum is σ = 112112013402. Its totient is φ = 112112013400.

The previous prime is 112112013353. The next prime is 112112013407. The reversal of 112112013401 is 104310211211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87556810000 + 24555203401 = 295900^2 + 156701^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112112013401 is a prime.

It is a super-3 number, since 3×112112013401³ (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 112112013401.

It is not a weakly prime, because it can be changed into another prime (112112013407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056006700 + 56056006701.

It is an arithmetic number, because the mean of its divisors is an integer number (56056006701).

Almost surely, 2^112112013401 is an apocalyptic number.

It is an amenable number.

112112013401 is a deficient number, since it is larger than the sum of its proper divisors (1).

112112013401 is an equidigital number, since it uses as much as digits as its factorization.

112112013401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 112112013401 its reverse (104310211211), we get a palindrome (216422224612).

The spelling of 112112013401 in words is "one hundred twelve billion, one hundred twelve million, thirteen thousand, four hundred one".